Assign By Reference
In the first of these, PHP references allow you to make two variables refer to the same content. Meaning, when you do:
it means that
$a and
$b point to the same content.
Note:
$a and $b are completely equal here. $a is not pointing to $b or vice versa. $a and $b are pointing to the same place.
Note:
If you assign, pass, or return an undefined variable by reference, it will get created.
Example #1 Using references with undefined variables
<?php
function foo(&$var) { }
foo($a); // $a is "created" and assigned to null
$b = array();
foo($b['b']);
var_dump(array_key_exists('b', $b)); // bool(true)
$c = new StdClass;
foo($c->d);
var_dump(property_exists($c, 'd')); // bool(true)
?>
The same syntax can be used with functions that return references, and with the new operator (since PHP 4.0.4 and before PHP 5.0.0):
Since PHP 5,
new returns a reference automatically, so using
=& in this context is deprecated and produces an
E_DEPRECATED message in PHP 5.3 and later, and an
E_STRICT message in earlier versions. (Technically, the difference is that, in PHP 5, object variables, much like resources, are a mere pointer to the actual object data, so these object references are not "references" in the same sense used before (aliases). For more information, see
Objects and references.)
Warning If you assign a reference to a variable declared global inside a function, the reference will be visible only inside the function. You can avoid this by using the $GLOBALS array.
Example #2 Referencing global variables inside functions
<?php
$var1 = "Example variable";
$var2 = "";
function global_references($use_globals)
{
global $var1, $var2;
if (!$use_globals) {
$var2 =& $var1; // visible only inside the function
} else {
$GLOBALS["var2"] =& $var1; // visible also in global context
}
}
global_references(false);
echo "var2 is set to '$var2'\n"; // var2 is set to ''
global_references(true);
echo "var2 is set to '$var2'\n"; // var2 is set to 'Example variable'
?>
Think about
global $var; as a shortcut to
$var =& $GLOBALS['var'];. Thus assigning another reference to
$var only changes the local variable's reference.
Note:
If you assign a value to a variable with references in a foreach statement, the references are modified too.
Example #3 References and foreach statement
<?php
$ref = 0;
$row =& $ref;
foreach (array(1, 2, 3) as $row) {
// do something
}
echo $ref; // 3 - last element of the iterated array
?>
While not being strictly an assignment by reference, expressions created with the language construct array() can also behave as such by prefixing & to the array element to add. Example:
Note, however, that references inside arrays are potentially dangerous. Doing a normal (not by reference) assignment with a reference on the right side does not turn the left side into a reference, but references inside arrays are preserved in these normal assignments. This also applies to function calls where the array is passed by value. Example:
In other words, the reference behavior of arrays is defined in an element-by-element basis; the reference behavior of individual elements is dissociated from the reference status of the array container.
Pass By Reference
The second thing references do is to pass variables by reference. This is done by making a local variable in a function and a variable in the calling scope referencing the same content. Example:
will make
$a to be 6. This happens because in the function
foo the variable
$var refers to the same content as
$a. For more information on this, read the
passing by reference section.
PHP General