Description
void
unset ( mixed var [, mixed var [, mixed ...]])
unset() destroys the specified variables. Note that in PHP 3, unset() will always return TRUE (actually, the integer value 1). In PHP 4, however, unset() is no longer a true function: it is now a statement. As such no value is returned, and attempting to take the value of unset() results in a parse error.
Example 1. unset() example <?php // destroy a single variable unset($foo);
// destroy a single element of an array unset($bar['quux']);
// destroy more than one variable unset($foo1, $foo2, $foo3); ?> |
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The behavior of unset() inside of a function can vary depending on what type of variable you are attempting to destroy.
If a globalized variable is unset() inside of a function, only the local variable is destroyed. The variable in the calling environment will retain the same value as before unset() was called.
The above example would output:
If a variable that is PASSED BY REFERENCE is unset() inside of a function, only the local variable is destroyed. The variable in the calling environment will retain the same value as before unset() was called.
The above example would output:
If a static variable is unset() inside of a function, unset() destroys the variable and all its references.
The above example would output:
If you would like to unset() a global variable inside of a function, you can use the $GLOBALS array to do so:
Note: Because this is a language construct and not a function, it cannot be called using variable functions
See also isset(), empty(), and array_splice().